Friday, March 20, 2009

 

Fri-Day 2

AP Chem- went through an example in which a salt's solubility was determined (a saturated solution must be formed); this value was then converted to the salt's molar solubility. A salt's molar solubility is used to find, by stoichiometry, the EQUILIBRIUM concentrations of its dissolved ions; these concentrations can then be plugged into the salt's Ksp expression in order to find its equilibrium constant at a given temperature.
We completed every practical permutation of empirical salt formulas with respect to Ksp and molar solubility, "s".
Next week, we will do the most difficult equilibrium problems in this course. Much practice is required.

Bio 6/7/8- took the Meiosis/Reproduction exam.



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